(a+1)*x^2-4ax+2a=0

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Solution for (a+1)*x^2-4ax+2a=0 equation:


Simplifying
(a + 1) * x2 + -4ax + 2a = 0

Reorder the terms:
(1 + a) * x2 + -4ax + 2a = 0

Reorder the terms for easier multiplication:
x2(1 + a) + -4ax + 2a = 0
(1 * x2 + a * x2) + -4ax + 2a = 0

Reorder the terms:
(ax2 + 1x2) + -4ax + 2a = 0
(ax2 + 1x2) + -4ax + 2a = 0

Reorder the terms:
2a + -4ax + ax2 + 1x2 = 0

Solving
2a + -4ax + ax2 + 1x2 = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-1x2' to each side of the equation.
2a + -4ax + ax2 + 1x2 + -1x2 = 0 + -1x2

Combine like terms: 1x2 + -1x2 = 0
2a + -4ax + ax2 + 0 = 0 + -1x2
2a + -4ax + ax2 = 0 + -1x2
Remove the zero:
2a + -4ax + ax2 = -1x2

Combine like terms: -1x2 + x2 = 0
2a + -4ax + ax2 + x2 = 0

The solution to this equation could not be determined.

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